Master power functions for VCE Maths Methods with plain English intuition, clear graphs, worked examples and an auto marked practice test. Negative and fractional powers, domains and key features made simple.
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Take the simple letter x and ask what happens when you raise it to different powers. Square it and you get the gentle bowl of a parabola. Cube it and the curve learns to dip below the axis. Flip the power negative and the graph splits in two and races toward invisible walls. Turn the power into a fraction and you have square roots and cube roots. Every one of these is the same idea wearing a different number, and once you can read the number you can picture the graph before you draw a single point.
What a power function actually is
A power function is anything of the form y=xn, where the variable sits on the bottom and the power n is a fixed number. That power n is the whole personality of the graph. It decides the shape, where the graph is allowed to live, and how it behaves near the edges.
There are three families worth knowing, and they all hide inside that one little n.
Positive whole powers like x2, x3, x4. These are smooth curves that pass through the origin.
Negative powers like x−1, x−2. A negative power means “one over”, so x−2=x21. These graphs have a forbidden value where the bottom would be zero.
Fractional powers like x1/2, x1/3. A fractional power is a root, so x1/2=x and x1/3=3x.
Odd powers versus even powers
For the whole number powers, the single most useful question is whether n is odd or even.
An even power such as x2 or x4 turns every input positive, because a negative times a negative is positive. So the graph sits entirely above the axis, looks like a bowl, and is a mirror image across the y axis. Because the left and right sides match, the same height is reached twice, which makes an even power many to one, so it has no inverse function unless you chop the domain in half.
An odd power such as x3 or x5 keeps the sign of the input. Feed in a negative and you get a negative out. The graph flows from bottom left to top right through the origin, never repeats a height, and so it is one to one. That is why y=x3 has a proper inverse function but y=x2 does not.
The even power y = x² (blue) is a bowl sitting above the axis and reaching each height twice, while the odd power y = x³ (red) rises through the origin and hits every height exactly once.
The two traps in the domain
Here is where careful students pull ahead. The maximal domain is the full set of x values you are allowed to feed in, and only two things can ban a value.
First, you can never divide by zero. So any negative power, which is secretly a fraction, must throw out the value that makes the bottom zero. For x−2=x21 the banned value is x=0, giving a domain of R∖{0}.
Second, you can never take an even root of a negative. A power of 21 is a square root and a power of 41 is a fourth root, and both reject negatives, so their domain starts at zero: [0,∞). But an odd root is relaxed about signs. A power of 31 is a cube root, and since a negative cubed is negative, you are allowed to feed in negatives. So x1/3 has domain all of R, and (−8)1/3=−2 is perfectly valid.
Differentiating a power function
The good news is that one rule handles every case, fractions and negatives included. Bring the power down to the front as a multiplier, then knock the power down by one.
dxd(xn)=nxn−1
So dxd(x1/2)=21x−1/2, which you tidy into 2x1. The mistake examiners see again and again is keeping the original power, or worse, adding one to it, which is antidifferentiation in disguise. Subtract one from the power, never add. Tidy your negative powers back into fractions and roots so your final answer is easy to read and easy to mark.
See these moves in action in the Worked Examples tab, then test yourself in Try It.
Lock it in with active recall
Active recall
Answer from memory first, then flip. Rate yourself and each card returns on a spaced schedule (1 → 3 → 7 → 16 days).
Rewrite a negative powerx−n as a fraction.
x−n=xn1 — a negative power means reciprocal.
Rewrite a fractional powerx1/n.
x1/n=nx — a fractional power means a root.
What is the maximal domain of x−2?
R∖{0}. Since x−2=x21, only x=0 is banned (it makes the bottom zero).
Why does the cube root of a negative work but the square root does not?
A cube root is an odd root, and an odd number of negatives multiplies to a negative, so negatives are allowed. A square root is even, and no real square is negative, so even roots reject negatives.
State the rule for differentiating any power, and the one-word warning.
dxd(xn)=nxn−1 — bring the power down, then subtract one (never add).
Which power functions are one to one and so have an inverse without restricting the domain?
The odd powers like y=x3. Even powers (x2, x4) and x−2 are many to one and fail the horizontal line test.
Recall · Inverse Functions
A function has an inverse function only when it is what?
One to one — each output comes from exactly one input. Otherwise restrict the domain to force it.
Recall · Polynomial Functions
What does a squared factor like (x−2)2 do at the x axis?
The curve touches and turns there, making (2,0) a turning point on the axis.
Worked examples
Worked Example 1Sketching a truncus, from a real exam
Let g:R∖{−3}→R,g(x)=(x+3)21−2. Sketch the graph of y=g(x), labelling all asymptotes with their equations and axis intercepts with their coordinates.
1
Identify the asymptotes from the truncus form.
x=−3,y=−2
2
Find the y-intercept by setting x=0.
g(0)=91−2=−917
3
Find the x-intercepts by setting g(x)=0. The examiner report flags failing to label asymptotes and sketching a hyperbola by mistake.
(x+3)2=21⇒x=−3±21
Answer
Truncus with asymptotes x=−3,y=−2;y-int (0,−917);x-ints (−3±21,0)
VCAA 2024 Mathematical Methods Exam 1, Q3a
Worked Example 2Sketching a hyperbola, from a real exam
Sketch the graph of f(x)=2−x−13, labelling all asymptotes with their equations and axial intercepts with their coordinates.
1
Identify the asymptotes from the translated hyperbola form.
x=1andy=2
2
Find the y-intercept by setting x=0.
f(0)=2−−13=5⟹(0,5)
3
Find the x-intercept by setting f(x)=0. The report notes students often mislabel the y-intercept as (5,0).
2=x−13⟹x=25⟹(25,0)
Answer
Asymptotes x=1,y=2;x-int (25,0);y-int (0,5)
VCAA 2023 Mathematical Methods Exam 1, Q3a
Worked Example 3Reading off the family
Sketch the shape and state the domain and range of f(x)=x−2.
1
Rewrite the negative power as a fraction so the shape is obvious.
x−2=x21
2
You cannot divide by zero, so x=0 is banned. Everywhere else is fine.
domain=R∖{0}
3
Squaring makes the bottom positive, so f(x) is always above the axis. As x→0 it shoots up; as x→±∞ it sinks toward 0.
range=(0,∞)
Answer
domain R∖{0},range (0,∞), with asymptotes x=0 and y=0
Worked Example 4A fractional power
State the maximal domain of g(x)=x1/2 and find g′(x).
1
A power of 21 is a square root. You cannot square root a negative, so x must be zero or more.
g(x)=x,domain=[0,∞)
2
Differentiate using the rule that the power drops by one and comes out the front.
g′(x)=21x−1/2
3
Tidy the negative power into a root so it is readable.
g′(x)=2x1
Answer
domain [0,∞),g′(x)=2x1
Worked Example 5A cube root with a sign
Find f(−8) for f(x)=x1/3, then state the domain of f.
1
A power of 31 is a cube root. Cube roots of negatives are allowed, because a negative times a negative times a negative is negative.
f(−8)=3−8=−2
2
Since odd roots accept negatives, every real number works.
domain=R
Answer
f(−8)=−2,domain R
Practice questions
Practice test
Try it yourself
6 questions, 8 marks
Choose your answers, then submit to see your score and the full worked solutions.
Multiple choice is marked for you, just like Exam 2 Section A.
Q1.The maximal domain of f(x)=x−3 is:
1mark
Need a hint?
Rewrite the negative power as a fraction. Which single value would make the denominator zero?
Show worked solution
Since x−3=x31, the only banned value is the one that makes the denominator zero, namely x=0. Every other real number is allowed, so the domain is R∖{0}. Option C, [0,∞), is the trap of treating a negative power like a square root and wrongly cutting off the negatives.
Q2.The maximal domain of h(x)=x1/4 is:
1mark
Need a hint?
A power of one quarter is a fourth root. Is that root odd or even, and which signs does an even root reject?
Show worked solution
A power of 41 is a fourth root, which is an even root. Even roots reject negatives, so x≥0. Zero is fine because 40=0, giving [0,∞). Option B, R, is the common slip of treating every fractional power like a cube root.
Q3.The exact value of (−27)1/3 is:
1mark
Need a hint?
A power of one third is a cube root. Ask yourself what number cubed gives negative twenty seven.
Show worked solution
A power of 31 is a cube root, an odd root, so negatives are allowed. Since (−3)3=−27, the answer is −3. Option A treats the cube root of a negative as undefined, which is the mistake students make when they confuse odd roots with even roots.
Q4.If f(x)=x1/2, then f′(x) equals:
1mark
Need a hint?
Bring the power to the front, then subtract one from the index. Remember to subtract, never add.
Show worked solution
Bring the power 21 to the front and reduce the power by one: f′(x)=21x−1/2. Option B keeps the original power instead of subtracting one. Option D adds one to the power, which is antidifferentiation, the reverse operation.
Q5.Which power function is a one to one function on its maximal domain, and so has an inverse function?
1mark
Need a hint?
Apply the horizontal line test. Which of these keeps the sign of the input and never repeats a height, odd or even powers?
Show worked solution
A function is one to one when no horizontal line cuts it more than once. The odd power y=x3 rises steadily and passes this test, so it has an inverse. The even powers y=x2 and y=x4 are many to one, since for example x=2 and x=−2 give the same output, so they fail without a domain restriction. The same many to one issue affects y=x−2.
Q6.Let f(x)=x−1/2. State the maximal domain of f, then find f′(x), expressing your answer with a positive index in the denominator.
3marks
Work this on paper. The worked solution appears once you submit.
Show worked solution
A power of −21 means f(x)=x1. The square root needs x≥0, and the denominator cannot be zero, so x=0 is also banned. The maximal domain is therefore
(0,∞).
Differentiating, bring the power −21 to the front and subtract one from the index:
f′(x)=−21x−3/2.
Writing this with a positive index in the denominator:
f′(x)=−2x3/21=−2x31.
Frequently asked questions
What is the domain of a power function with a negative power?
Every real number except the one that makes the bottom zero. A negative power is secretly a fraction, so you must throw out x equals zero, giving all real numbers except zero.
Why does the cube root of a negative number work but the square root does not?
A cube root is an odd root, and an odd number of negatives multiplies back to a negative, so negatives are allowed. A square root is an even root, and no real number squared gives a negative, so even roots reject negatives.
How do you differentiate a function with a fractional or negative power?
Use the same rule as for any power. Bring the power to the front as a multiplier, then subtract one from the power. The rule works for fractions and negatives exactly as it does for whole numbers, so there is nothing extra to learn.