Physics · Units 3 & 4

The Wave Model of Light

Understand the wave model of light the easy way, with plain English intuition, an interactive simulation, electromagnetic waves, standing waves on a string, worked examples and an auto marked practice test. VCE Physics Units 3 and 4.

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Light is a wave, and not the kind that travels through water or air. It is a ripple in the electric and magnetic fields themselves, and it can race across totally empty space. Wiggle an electric charge back and forth and you send a disturbance outward at an astonishing fixed speed. That self carrying ripple is what your eyes catch when they see colour.

Light is an electromagnetic wave

Picture an electric charge being shaken up and down. As it moves it makes a changing electric field, and a changing electric field always creates a changing magnetic field alongside it. That new magnetic field is also changing, so it creates another electric field, and the two keep handing the baton back and forth as the wave races away.

  • The wave is transverse: the electric and magnetic fields point across the direction the wave travels, not along it.
  • It needs no medium. Because each field keeps regenerating the other, the wave carries itself, which is how sunlight crosses the vacuum of space to reach us.
  • Every electromagnetic wave travels at the same speed in a vacuum, c=3.0×108c = 3.0 \times 10^{8} m/s, whether it is radio, red light or X rays.
direction of travelelectric fieldmagnetic field

The red curve is the electric field and the blue dashed curve is the magnetic field. They are at right angles to each other and both at right angles to the direction the wave travels. That side to side wiggle is what makes light a transverse wave.

Every wave obeys one short rule that ties together how fast it goes, how many wiggles pass each second, and how long each wiggle is. For light that rule is speed equals frequency times wavelength.

The speed vv is in metres per second, the frequency ff is in hertz (wiggles per second), and the wavelength λ\lambda is the length of one full wiggle in metres. For light in a vacuum the speed is locked at cc, so c=fλc = f\lambda. This means colours with a shorter wavelength must have a higher frequency, because the product always has to equal the same cc.

Standing waves on a string

Now send a wave down a string that is tied down at both ends. The wave races to the far end, bounces back, and the returning wave overlaps the one still coming. When they line up just right the string settles into a frozen looking pattern called a standing wave.

A standing wave forms when a travelling wave superposes with its own reflection. The string is pinned at both ends, so those ends can never move: they are nodes. In between sit the antinodes, the points that swing with the biggest movement. Only certain wavelengths fit neatly between the fixed ends, and they are given by λ=2Ln\lambda = \dfrac{2L}{n}, where LL is the length of the string and n=1,2,3,…n = 1, 2, 3, \ldots counts the antinodes (the harmonic number).

antinodenode (fixed point)length L, three antinodes (n = 3)

The two dashed curves, red and blue, show the two extremes the string swings between. Where they cross are the nodes, which never move, and the fat middles are the antinodes, where the string moves most. This pattern has three antinodes, so it is the third harmonic with n=3n = 3.

See it for yourself

Send a single pulse or a continuous wave down the string and watch it reflect off the fixed end. Set the end to Fixed, turn on Oscillate, and tune the frequency until the reflected wave lines up with the incoming one and a steady standing wave appears, with still nodes and big swinging antinodes.

Interactive simulation, Wave on a String Source: PhET Interactive Simulations, University of Colorado Boulder (CC BY 4.0)

How to actually solve one

These questions come in two flavours, and both are quick once you spot which is which.

  1. For a light question, reach for c=fλc = f\lambda. Make sure the wavelength is in metres (nanometres are ×10−9\times 10^{-9} m), then rearrange for whatever is missing.
  2. For a standing wave on a string fixed at both ends, use λ=2Ln\lambda = \dfrac{2L}{n}, where nn is the number of antinodes.
  3. Count antinodes carefully: n=1n = 1 is the fundamental with the longest wavelength, n=2n = 2 is the second harmonic, and so on.
  4. If you need the speed of the wave on the string, combine the two ideas with v=fλv = f\lambda.

Try one: a string of length 0.900.90 m is fixed at both ends and vibrates in its third harmonic (three antinodes). Find the wavelength of the standing wave.

Lock it in with active recall

Cover the answer and say each one out loud before you flip. Rate yourself honestly — the cards you find hard come back sooner, the ones you know are spaced further out.

Active recall

Answer from memory first, then flip. Rate yourself and each card returns on a spaced schedule (1 → 3 → 7 → 16 days).

What kind of wave is light, and what is wiggling?
Why can light travel through empty space when sound cannot?
Write the wave equation for light in a vacuum.
Do red and blue light travel at the same speed in a vacuum?
What is the difference between a node and an antinode?
Give the allowed wavelengths of a string fixed at both ends.
Recall · Diffraction and Interference
What does the double-slit fringe pattern prove about light?
Recall · The Photoelectric Effect
Which experiment shows light behaving as particles, not waves?

See the recipe in action in the Worked Examples tab, then test yourself in Try It.

Worked examples

Worked Example 1Frequency of red light

Red light has a wavelength of 700700 nm, which is 7.0×10−77.0 \times 10^{-7} m. Taking the speed of light as c=3.0×108c = 3.0 \times 10^{8} m/s, find its frequency.

  1. 1

    Light is an electromagnetic wave, so it obeys the wave equation v=fλv = f\lambda. For light in a vacuum the speed is cc, so c=fλc = f\lambda.

    c=fλc = f\lambda
  2. 2

    Rearrange to make the frequency the subject.

    f=cλf = \dfrac{c}{\lambda}
  3. 3

    Substitute the speed of light and the wavelength in metres.

    f=3.0×1087.0×10−7f = \dfrac{3.0 \times 10^{8}}{7.0 \times 10^{-7}}
  4. 4

    Work out the division to get the frequency in hertz.

    f=4.3×1014 Hzf = 4.3 \times 10^{14} \text{ Hz}
Answer
f=cλ=3.0×1087.0×10−7=4.3×1014 Hzf = \dfrac{c}{\lambda} = \dfrac{3.0 \times 10^{8}}{7.0 \times 10^{-7}} = 4.3 \times 10^{14} \text{ Hz}
Worked Example 2Wavelength of a standing wave

A string of length 1.21.2 m is fixed at both ends and vibrates with 33 antinodes, which is the third harmonic. Find the wavelength of the standing wave.

  1. 1

    A string fixed at both ends has a node at each end. The allowed wavelengths are λ=2Ln\lambda = \dfrac{2L}{n}, where nn is the number of antinodes.

    λ=2Ln\lambda = \dfrac{2L}{n}
  2. 2

    Here the length is L=1.2L = 1.2 m and the harmonic number is n=3n = 3.

    λ=2×1.23\lambda = \dfrac{2 \times 1.2}{3}
  3. 3

    Work out the top, then divide.

    λ=2.43=0.80 m\lambda = \dfrac{2.4}{3} = 0.80 \text{ m}
Answer
λ=2Ln=2×1.23=0.80 m\lambda = \dfrac{2L}{n} = \dfrac{2 \times 1.2}{3} = 0.80 \text{ m}

Practice questions

Practice test

Try it yourself

5 questions, 6 marks

Choose your answers, then submit to see your score and the full worked solutions. Multiple choice is marked for you, just like Exam 2 Section A.

Q1.Light is best described as a:

1mark
Need a hint?
Light has electric and magnetic fields that wiggle across the direction of travel, and it crosses empty space.

Q2.A wave has a frequency of 5.0×10145.0 \times 10^{14} Hz and travels at c=3.0×108c = 3.0 \times 10^{8} m/s. Its wavelength is closest to:

1mark
Need a hint?
Rearrange c=fλc = f\lambda to get λ=c/f\lambda = c/f.

Q3.Compared with red light, blue light in a vacuum travels at:

1mark
Need a hint?
Every electromagnetic wave travels at the same speed in a vacuum.

Q4.A string of length 1.01.0 m is fixed at both ends and vibrates in its fundamental mode, with 11 antinode. The wavelength of the standing wave is:

1mark
Need a hint?
Use λ=2Ln\lambda = \dfrac{2L}{n} with n=1n = 1.

Q5.A string of length 0.600.60 m is fixed at both ends and vibrates in its second harmonic, with 22 antinodes. Find the wavelength of the standing wave. Show your working.

2marks

Work this on paper. The worked solution appears once you submit.

Frequently asked questions

Why can light travel through empty space when sound cannot?
Light is an electromagnetic wave. A changing electric field creates a changing magnetic field, which creates a changing electric field, and so on, so the wave carries itself along and needs no medium. Sound is a vibration of particles, so it dies out where there are no particles, like in the vacuum of space.
Do all colours of light travel at the same speed?
Yes, in a vacuum every electromagnetic wave travels at the same speed, 3.0 times 10 to the power 8 metres per second. Different colours have different frequencies and wavelengths, but the product of frequency and wavelength is always that same speed.
What is the difference between a node and an antinode?
A node is a point on a standing wave that never moves, where the wave is always still. An antinode is a point that swings with the largest movement. On a string fixed at both ends the two ends are always nodes, and the antinodes sit in between.